This is a genetics problem. What are the allele frequencies, genotype frequencies, and phenotype frequencies in this population? The information given is A=.53 B= .13 and O= .26 .I know that since it is blood typing, codominance occurs and that the Hardy Weinberg formula must also be used (p+q=1 and p2+2pq+q2=1)..where the p and the q are squared in the second equation. Even if you only know how to do one of them, that will be much appreciated! Thank you!!
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Verified answer
You did not specifiy if the numbers given were for the allele frequency or the phenotype frequency. Since there are no AB individuals I will assume it is allelle frequency.
You can not use HW since there are 3 allelles (A, B, O) not just 2.
The allele frequency is given (I assume) the possible outcomes are.
AB
AO
AA
BA
BB
BO
OA
OB
OO
But only 6 of these are unique genotypes and only 4 phenotype. but each unique event is the frequency times teh frequency and then you would multiple this by 2 if there are 2 wasy to have it
Eg: There is only 1 way to have O blood type so the phenotypic frequency is
0.26*0.26=0.52 the genotypic frequncy would be the same in this case
Eg #2
A phenotype is AO, OA, AA so there are 3 different number to add together and AO and OA are identical.
2(0.53*0.26)+ (0.53*0.53)=0.4187
Note the 2 genotypes that make up A blood types are expressed by the first half of the equation and the second half
AO=2(0.53*0.26)
AA=(0.53*0.53)
You should be able to figure out the rest on your own.