This is an easy one if you use dimensional analysis. Avogadro's number is 6.023 x 10^23 with the units of particles per mol. Also, 1 mole of Ag = 107.9 g So start here:
1 Ag particle x (1 mol / 6.023 x 10^23 particle) x (107.9 g Ag / 1 mol Ag) = 1.97 x 10^–22 g Ag
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Verified answer
Since Avogadro's number of atoms = its atomic weight, one atom would be 1/6.022 x 10^23 of its atomic weight.
EX:
AW for Ag is 107.8682 g/mole
(107.8682 g/mole)(1mole /6.022 x 10^23 atoms)
= 1.791 x 10^(-22) g/atom
This is an easy one if you use dimensional analysis. Avogadro's number is 6.023 x 10^23 with the units of particles per mol. Also, 1 mole of Ag = 107.9 g So start here:
1 Ag particle x (1 mol / 6.023 x 10^23 particle) x (107.9 g Ag / 1 mol Ag) = 1.97 x 10^–22 g Ag