Calcium oxalate, CaC2o4, is very insoluble in water. What mass of sodium oxalate, Na2C2O4, is required to precipitate the calcium ion from 37.5 mL of 0.104 M CaCl2 solution?
A solution of the sparingly soluble base Ca(OH)2 is prepared in a volumetric flask by dissolving 5. 21mg of Ca(OH)2 to a total volume of 1000. mL. Calculate the molarity and the normality of the solution
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Verified answer
CaCl2 + Na2C2O4 >>>> CaC2O4 +2 NaCl
Mass of CaCl2 = ( 0.375 L ) ( 0.104 mole / L ) (110.9 g/ mole)
Mass of CaCl2 = 4.33 g
Mass of CaC2O4 = (4.33 g) ( 128 / 110.9 ) = 5.0 g ans.
No of moles Ca(OH)2 = 0.00521 g / 74 g /mole = 7.04e-5
Molarity = no of moles solute / Liter soln
= 7.04 e-5 moles / 1 liter soln = 7.04 e-5 Molar ans.
No of equivalent = (0.00521) (2) / 74 = 1.41 e-4
Normality = no of equivalent / L soln
Normality = 1.41 e-4 / 1 liter = 1.41 e-4 N ans