Chemistry Stoichiometry!?
You are given 40nM of a compound. Its molecular weight is 280 g/mol. How much of the following do you have?
mol/mL?
mmol/uL?
mg/L?
ng/L?
%(w/v) ?
How do I do these questions?!
More Questions From This User See All
Answers & Comments
Verified answer
1 nM = 1 nmoles / 1 L
40nmoles = 40x10^-9moles and 1L = 1000ml for 4x10^-11moles/ml
40nmole = 40x10^-6mmoles and 1L = 1x10^6µL 4x10^-11mmole/µl
40nmoles = 40x10^-9moles
40x10^-9moles x 280g/mole = 1.12x10^-5g = 1.12x10^-2mg for 0.0112mg/L
0.0112mg/L x 1000ng/mg = 11.2ng/L
w/v = % mass / 100ml solution
40nmoles x 1x10^-6moles/nmole = 4x10^-5moles
4x10^-5moles x 280g/mole = 0.0112g for 0.0112g/L
0.0112g / 1000ml x 100% = 0.112%