A simple series R-C circuit in a defibrillator has capacitance C = 25 millifarad and effective resistance R = 4 ohm. The capacitor is fully charged.
Then, at t = 0 s, the defibrillator is activated, so essentially a switch is closed allowing current to flow through the resistance and capacitor.
At t = 0.5 s, what fraction (approximately) of the total stored charge, has flowed from the capacitor?
Select one:
a. 99%
b. 63%
c. 80%
d. 33%
e. 10%
I've used I=dQ/dt and it has given me 0.05A but I don't know where to go from here, am I on the right track?
Copyright © 2024 Q2A.MX - All rights reserved.
Answers & Comments
Verified answer
Lets use e-t/rc
25e-3 * 4 = .1 so TC = .1 seconds
So 2.71828^-5 = .006 = approx. 99% discharge
answer is: a) 99%
The battery in flight is a fast discharge, the battery is easy to heat. Charge, so long as the charge, the battery is basically just a little micro thermal. Battery inability to fly the aircraft rotor rotation, can not fly, can be charged, not to be used will not be diverted to recharge, I charge so there are just flying off the battery do not immediately charge (cooling about one hour and then charge remember!!)