For the vertex, the x value will always be exactly between the two x- intercepts. So, the x value for the vertex will be -1. Now, plug in -1 into the equation for the y value. You get -4.
y = x² - 4x - 2 Parabola is in common variety ax² + bx + c, the placement a = a million, b = - 4, c = - 2 Equation of the axis of symmetry is x = - b/2a = - - 4/2(a million) = 2 this is the x-coordinate of the vertex. fixing the function for this cost components the y-coordinate. y = 2² - 4(2) - 2 = 4 - 8 - 2 = - 6 Vertex is (2, - 6).
Answers & Comments
Y-intercept: x= 0
0^2 +2(0)- 3
y= -3
X-intercept: y=0
factor,
x^2+2x-3
(x -1) (x+3)
x= 1 and x = -3
For the vertex, the x value will always be exactly between the two x- intercepts. So, the x value for the vertex will be -1. Now, plug in -1 into the equation for the y value. You get -4.
Therefore, the vertex is (-1, -4)
Hope this helps :)
y = x² - 4x - 2 Parabola is in common variety ax² + bx + c, the placement a = a million, b = - 4, c = - 2 Equation of the axis of symmetry is x = - b/2a = - - 4/2(a million) = 2 this is the x-coordinate of the vertex. fixing the function for this cost components the y-coordinate. y = 2² - 4(2) - 2 = 4 - 8 - 2 = - 6 Vertex is (2, - 6).