What volume of 2, measured at 82.1 C and 713 mm hg will be produced by the decomposition of 5.71g kclo3?(r= 0.08206)
molar mass of kclo3 is 122.521
should the answer be 5.55L and not 2.17 L?
Thanks for your time
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Verified answer
5.5537964L that was too easy
The decomposition reaction is
2KClO3 ==> 2KCl + 3O2
5.71 g KClO3 x (1 mole KClO3 / 122.6 g KClO3) = 0.0466 moles KClO3
The balanced equation tells us that 2 moles of KClO3 produce 3 moles of O2.
0.0466 moles KClO3 x (3 moles O2 / 2 moles KClO3) = 0.0699 moles O2
Use the ideal gas law to find the volume of 0.0699 moles O2.
82.1 C + 273 = 355 K
713 mm Hg x (1 atm / 760 mm Hg) = 0.938 atm
PV = nRT
V = nRT / P = (0.0699)(0.08206)(355) / (0.938) = 2.17 L