How much does S decrease?
S and T are related by the following relationship . S=k/T , where k is a constant. If S increases by 50% by how much does T decreases? and vice versa if T increases by 50% how much does S decreases?
the answer is suppose to be 33.33% but I don't know why.
More Questions From This User See All
Answers & Comments
It's easier to show the algebra for "if T increases by 50% how much does S decrease?" first.
If you start with T0 then S0=k/T0.
If T then increases by 50%, the new value is T1=T0+0.50*T0=(1+0.50)T0=(3/2)*T0.
The corresponding S1 = k/(T1) = k/[(3/2)*T0] .
For the compound fraction 1/(3/2) invert and multiply to get S1=(2/3)*(k/T0) =(2/3)S0.
The amount of decrease is S0-S1 = (1-(2/3))*S0=(1/3)S0.
The other problem is nearly identical since it S0=k/T0 then S1= (3/2)*S0 will lead to T1=(2/3)T0 etc.