A small college has 3254 students in 2003 and 3752 students in 2005 the enrollment follows a linear pattern. How many students will the college have in 2006?
The increase in 2 years is 3752-3254=498. Because of linearity, this means 249 per year.
Therefore in 2006, the number of students in 2006 is 3752+249=4001.
let the x be the year and y be the number of students.
x y
2003 3254
2005 3752
2006 ?
m=(y2-y1)/(x2-x1) =====> formula for the slope
m=(3752-3254)/(2005-2003)
m=498/2
m=249
b=y-mx =====> formula for the y-intercept
b=3254-249(2003) =====> substitute any of the given points for x and y. Here, I use the first point.
b=3254-498747
b= -495493
y=mx+b =====>linear equation slope-intercept form
y=249x+(-495493) =====>substitute the slope (m) and the y-intercept (b)
y=249(2006)-495493 =====>substitute 2006 (x) to solve for the number of students (y) for the said year.
y=499494-495493
y=4001 =====> answer!
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The increase in 2 years is 3752-3254=498. Because of linearity, this means 249 per year.
Therefore in 2006, the number of students in 2006 is 3752+249=4001.
let the x be the year and y be the number of students.
x y
2003 3254
2005 3752
2006 ?
m=(y2-y1)/(x2-x1) =====> formula for the slope
m=(3752-3254)/(2005-2003)
m=498/2
m=249
b=y-mx =====> formula for the y-intercept
b=3254-249(2003) =====> substitute any of the given points for x and y. Here, I use the first point.
b=3254-498747
b= -495493
y=mx+b =====>linear equation slope-intercept form
y=249x+(-495493) =====>substitute the slope (m) and the y-intercept (b)
y=249(2006)-495493 =====>substitute 2006 (x) to solve for the number of students (y) for the said year.
y=499494-495493
y=4001 =====> answer!