Logarithms and exponentials?
2^ x+1 = 5^ 1-2x
ln x + ln(x-2)= ln(x+4)
2log base 5 of x= log base 5 of 9
^ (means to the power of)
any of these would help! thank you :))
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2^ x+1 = 5^ 1-2x
ln x + ln(x-2)= ln(x+4)
2log base 5 of x= log base 5 of 9
^ (means to the power of)
any of these would help! thank you :))
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1. You don't have any parentheses so I can't help here.
2. (ln a) + (ln b) = ln c ==>
e^((ln a) + (ln b)) = e^(ln c) ==>
e^(ln a) e^(ln b)) = e^(ln c)
and since e^(ln x) = x, you have:
ab = c
3. 5^(2log base 5 of x) = (5^(log base 5 of x))^2 = x^2