With some halogens, diborane (B2H6 ) forms trihalides even at low temperatures:
B2H6(g) + 6Cl2 (g) => 2BCl3 (g) + 6HCl(g) Δ Hrxn = –755.4 kJ
How much heat is evolved per kilogram of diborane that reacts?
Please help cause I try and try and still couldn't find out. The answer is 2.73 x 10^4 KJ
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Verified answer
moles B2H6 = 1000 g / 27.67 g/mol=36.1
1 : 755.4 = 36.1 : x
x = 27300 kJ =2.73 x 10^4 kJ