2x^2+12x+1=0
can u divide 2 to start the whole problem off
so u get x^2+6x+1/2 and then u complete the square
2x² + 12x + 1 = 0
2x² + 12x = - 1
2(x² + 6x) = - 1
x² + 6x = - 1/2
x² + 6x + 9 = - 1/2 + 9
(x + 3)² = - 1/2 + 18/2
(x + 3)² = 17/2
(x + 3)² = 8.5
x + 3 = √8.5
x + 3 = ± 2.92
x = ± 2.92 - 3
If x = 2.92 - 3,
x = - 0.08
If x = - 2.92 - 3,
x = - 5.92
x { - 5.92, - 0.08 }
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
Copyright © 2024 Q2A.MX - All rights reserved.
Answers & Comments
Verified answer
2x² + 12x + 1 = 0
2x² + 12x = - 1
2(x² + 6x) = - 1
x² + 6x = - 1/2
x² + 6x + 9 = - 1/2 + 9
(x + 3)² = - 1/2 + 18/2
(x + 3)² = 17/2
(x + 3)² = 8.5
x + 3 = √8.5
x + 3 = ± 2.92
x = ± 2.92 - 3
If x = 2.92 - 3,
x = - 0.08
If x = - 2.92 - 3,
x = - 5.92
x { - 5.92, - 0.08 }
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯