4y-8-2y+5=0
and what is the distributive property a explaination along with it would be suppper nice.
thanks again.
the distributive property is probably a little self-explanatory.
its like when you "distribute" the variables, and the numbers that are alike with each other.
in your equation:
4y - 8 - 2y + 5 = 0
4y and 2y are alike because they both have the "y" variable.
and 8 and 5 are alike because they are numbers.
so your equation becomes 2y - (-3)
this is because 4y - 2y = 2y and -8 + 5 = -3
i hope this helps.
=]
Move the terms around to match each other (4y-2y-8+5=0)
Combine like terms (2y-3=0)
Move the constant over (2y=3)
Divide both sides by 2 (y=1.5)
The distributive property applies to problems with parentheses. For example: 2(y+3)=0.
The distributive property tells you to multiply each term inside the parentheses by the term on the outside. 2y+6=0
This only works if the term is multiplied like in the above example. This would not be distributive: 2+(y+3)=0
regroup: 4y-2y-8+5=0
4y-2y=2y
-8+5=-3
so now you have,
2y-3=0
bring the 3 over by adding 3 to both sides
2y=3
divide both sides by 2
y=3/2
or
y=1.5
You're using the commutative property to change the grouping(8+10=10+8 property)
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Verified answer
the distributive property is probably a little self-explanatory.
its like when you "distribute" the variables, and the numbers that are alike with each other.
in your equation:
4y - 8 - 2y + 5 = 0
4y and 2y are alike because they both have the "y" variable.
and 8 and 5 are alike because they are numbers.
so your equation becomes 2y - (-3)
this is because 4y - 2y = 2y and -8 + 5 = -3
i hope this helps.
=]
Move the terms around to match each other (4y-2y-8+5=0)
Combine like terms (2y-3=0)
Move the constant over (2y=3)
Divide both sides by 2 (y=1.5)
The distributive property applies to problems with parentheses. For example: 2(y+3)=0.
The distributive property tells you to multiply each term inside the parentheses by the term on the outside. 2y+6=0
This only works if the term is multiplied like in the above example. This would not be distributive: 2+(y+3)=0
4y-8-2y+5=0
regroup: 4y-2y-8+5=0
4y-2y=2y
-8+5=-3
so now you have,
2y-3=0
bring the 3 over by adding 3 to both sides
2y=3
divide both sides by 2
y=3/2
or
y=1.5
You're using the commutative property to change the grouping(8+10=10+8 property)