How many grams of sodium metal are needed to make 29.3 grams of sodium chloride when sodium metal and chlorine gas are allowed to react? How did you get your answer?
2 Na + Cl2 → 2 NaCl
29.3 g NaCl (1mol/58.44g) = .501 moles NaCl
.501 moles NaCl (2 moles Na/2 moles NaCl) = .501 moles Na needed
.501 moles Na ( 23.00g/1mole) = 11.5g Na needed
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Verified answer
2 Na + Cl2 → 2 NaCl
29.3 g NaCl (1mol/58.44g) = .501 moles NaCl
.501 moles NaCl (2 moles Na/2 moles NaCl) = .501 moles Na needed
.501 moles Na ( 23.00g/1mole) = 11.5g Na needed