Verified answer

A dihybrid cross of TtRr and ttrr will give you the punnett square:

--- TR Tr tR tr

tr TtRr Ttrr ttRr ttrr

The genotypic ratios are: 25% TtRr, 25% Ttrr, 25% ttRr, 25% ttrr

The phenotypic ratios are: 25% expressing T and R phenotype, 25% expressing T and r phenotype, 25% expressing t and R phenotype, 25% expressing t and r phenotype.

This is what you call a test cross and whenever you test cross a heterozygous with a homozygous recessive individual, you get a 1:1:1:1 ratio.

Parent's Genotype: Tt Rr

Gametes: T t R r

Offspring Genotype and phenotype:

TR Rr

Tr tr

25% ratio of each

1:4 ratio

2 coin tosses of HH is what genotype ratio

ok, you're genotypic outcomes from the punnett sq. are superb. So now you will possibly be able to desire to be certain the phenotypes of those attainable offspring. properly it tells you than hornless is dominant over horned, so the two Hh persons would be hornless and the two hh persons would be horned. Now you will possibly be able to desire to calculate the genotypic and phenotypic ratio of those offspring. There are 2 Hh and 2 hh so the ratio is two:2 or you will possibly be able to simplify that to a million:a million. Now, to get the phenotypic ratio you do the comparable ingredient: there are 2 hornless and 2 horned, so 2:2, or as quickly as returned, a million:a million. wish this permits!