The half-life of a certain radioactive substance is 5 days.Initially, 8 grams of the substance is present.
How many grams will be present after:
a. 5 days?
b. 10 days?
c. 15 days?
d. 20 days?
e. 25 days?
f. 50 days?
pls with solution...
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Verified answer
4 g in 5 days because that is one half-life, and half will be gone after a half-life.
Each subsequent 5 days, half of the remainder will disappear, so that by day 10, there will be just 2 g left, thn 1 g by day fifteen, etc.
DAYS...REMAINING
0.................8g
5............(a) 4g
10..........(b) 2g
15..........(c) 1g
20..........(d) 0.5g
25..........(e) 0.25g
50..........(f) 0.0078125g
(0.125g at 30d, 0.0635g at 35d,
0.03125g at 40d, 0.015625g at 45d)
a - 4g
b - 2g
c - 1g
d - 0.5g
e - 0.25g
f - 0.0078125g