homework help please
log2 512 = 3x
2^(3x) = 512 = 2^(9)
3x = 9
x=3
examine the log by writing 2^(3x) = 512. thats just stating the problem.
well 2^9 happens to be 512. how convenient. thus 3x = 9. x = 3. BAM
9 = 3x
3 = x
turn it to exponential..
base is 2
answer is 512
power is 3x
2^3x = 512
512 is also equal to 2^9
so
2^3x = 2^9
since base of powers is the same (2)
3x=9
x=9/3
log(2)512=3x
2^3x=512
let y=3x
2^y=512
y=9
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Verified answer
log2 512 = 3x
2^(3x) = 512 = 2^(9)
3x = 9
x=3
examine the log by writing 2^(3x) = 512. thats just stating the problem.
well 2^9 happens to be 512. how convenient. thus 3x = 9. x = 3. BAM
9 = 3x
3 = x
turn it to exponential..
base is 2
answer is 512
power is 3x
2^3x = 512
512 is also equal to 2^9
so
2^3x = 2^9
since base of powers is the same (2)
3x=9
x=9/3
x=3
log(2)512=3x
2^3x=512
let y=3x
2^y=512
y=9
3x=9
x=3