The vertex?
Find the vertex, the line of symmetry, and the min or max value of f(x).
f(x) = -(x+6)^2 - 3
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Find the vertex, the line of symmetry, and the min or max value of f(x).
f(x) = -(x+6)^2 - 3
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Hi,
f(x) = -(x+6)² - 3 is in the form f(x) = a(x - h)² + k.
The vertex (h,k) is at (-6,-3).
The axis of symmetry is x = -6.
Because "a" is negative, the graph opens down so it has a maximum at its vertex. the maximum value is the vertex's y value of -3.
I hope that helps!! :-)