Verified answer

Let s be the number of shoes. Then the number of pants is 2s. The number of t-shirts is three-halves the number of pants, or (3/2)(2s) = 3s.

The different combinations of a shirt, pair of pants, and pair of shoes is s * 2s * 3s = 6s^3. This has to be greater than or equal to 365, the number of days in a year. So we have

6s^3 > = 365

This is

s^3 >= 365/6

s > = (365/6)^(1/3), which is about 3.93

So the smallest integer s can be is 4. Therefore, she needs at least 4 pairs of shoes, 8 pairs of pants, and 12 shirts. On a side note, this works for a leap year too.

She has "s" shoes

She has "2s" pants.

She has "3/2 x 2s" T-shirts

....and you have asked an un-answerable question.

I know you all have tender psychies and all that stuff.... but couldn't you (at least) proof-read before you hit "select" or "enter" or whatever?