tan2x=2tanx/1-tan^2x...Help?
How do you find the double-angle identity of tan2x=2tanx/1-tan^2x?
More Questions From This User See All
How do you find the double-angle identity of tan2x=2tanx/1-tan^2x?
Copyright © 2024 Q2A.MX - All rights reserved.
Answers & Comments
Verified answer
Use the tangent angle addition identity:
tan(A+B) = [tan(A) + tan(B)]/[1 - tan(A)tan(B)]
Plug in A = B = x:
tan(x+x) = [tan(x) + tan(x)]/[1 - tan(x)tan(x)]
tan(2x) = [2tan(x)]/[1 - tan^2(x)]
tan(x+y) = (tanx + tany) / (1 + tanxtany)
similarly
tan(2x)
= tan(x + x)
= (tanx + tanx) / (1 + tanxtanx)
= 2tanx / (1 + tan^2x)