Verified answer

ok. from da top.

2x+3y=90

3y=90-2x

y=30-(2\3)x

there ya go buddy

You need to get it into slope intercept (y=mx+b).

2x + 3y = 90

3y = -2x + 90 Subtract 2x from both sides.

y = (-2/3)x + 30 Divide both sides by three to isolate the y.

Slope-intercept form is y=mx + b. So isolate y on one side of the equation and solve. y= -2x/3 +30.

write each equation in slope-intercept form 2x+3y=90?

2x + 3y=90

-2x -2x=

3y= 90-2x

/3 /3

y=3/90-2x

then you switch it up a little and do x.

2x+3y=90

-3y -3y

2x=90-3y

/2 /2

x=2/90-3y

Slope intercept form: y=mx +b

The point is to get "y" by itself.

Subtract 2x from each side, then divide each side by three.

y=mx + c

2x+3y=90

y = -(2/3)x + 30 x = -(3/2)y + 45

y - slope x - slope

y= -2/3x+30