for standard form you write the number so it is a decimal between 1 and 10 (but not equal to 10), and then write it as multiplied by 10 to the power of how many spaces you needed to move the decimal point to get it to that form. for instance, above, you need to move the decimal point right three spaces, so it's to the power of -3 . moving right is negative, left positive.
Use the foil procedure to develop the denominator (1+i)^2 = 1 + i + i + i^2 = 1 + 2i - 1 = 2i so 2/(1+i)^2 = 2 / (2i) = 1/i multiply through i over i to get i / i^2 = i / (-1) = -i
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In the US, it looks like it already is in standard form!
0.00387 = (3.0 x 10^-3) + (8.0 x 10^-4) + (7.0 x 10^-5)
In Great Britain, standard form is the same as scientific notation in the US:
0.00387 = 3.87 x 10^-3
Hope that helps!
3.87 x 10^(-3)
for standard form you write the number so it is a decimal between 1 and 10 (but not equal to 10), and then write it as multiplied by 10 to the power of how many spaces you needed to move the decimal point to get it to that form. for instance, above, you need to move the decimal point right three spaces, so it's to the power of -3 . moving right is negative, left positive.
I think you have written it in standard form. You could also write 3.87 * 10^-3 but his is not more usual than your presentation.
Unusual inquiry -- if you mean scientific notation, where you have
a number between 1 and 10 times a power of 10 -- then
0.00387 would be 3.87 x 10^(-3)
The exponent of 10 indicates/provokes a move of the decimal
point left/right. (left if negative; right if positive)
3.87*10^-3
Idea is to shift the location of zeros
Use the foil procedure to develop the denominator (1+i)^2 = 1 + i + i + i^2 = 1 + 2i - 1 = 2i so 2/(1+i)^2 = 2 / (2i) = 1/i multiply through i over i to get i / i^2 = i / (-1) = -i
3.87 x 10^-3
3.87x10^(-3)