Please help, this is due in two hours! Please give answers for C and D!
The source sees 3.5||1.8+4.4 = 5.589Ω
Current leaving source = 9/5.589 = 1.61A
Voltage across R1 = 1.61A*4.4Ω = 7.09V
Therefore the voltage across R2 and R3 = 9 - 7.09 = 1.91V
The current in R2 = 1.91/3.5Ω = 0.547A = i2
The current in R3 = 1.91/1.8Ω = 1.06A = i3
Voltage across R2 and R3 = 9 - 7.09 = 1.91V
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The source sees 3.5||1.8+4.4 = 5.589Ω
Current leaving source = 9/5.589 = 1.61A
Voltage across R1 = 1.61A*4.4Ω = 7.09V
Therefore the voltage across R2 and R3 = 9 - 7.09 = 1.91V
The current in R2 = 1.91/3.5Ω = 0.547A = i2
The current in R3 = 1.91/1.8Ω = 1.06A = i3
Voltage across R1 = 1.61A*4.4Ω = 7.09V
Voltage across R2 and R3 = 9 - 7.09 = 1.91V